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[Codility] PermCheck 본문

코딩테스트/Codility

[Codility] PermCheck

꼬몽울 2021. 7. 29. 22:57

https://app.codility.com/programmers/lessons/4-counting_elements/perm_check/

 

PermCheck coding task - Learn to Code - Codility

Check whether array A is a permutation.

app.codility.com

def solution(A):
    A=sorted(A)
    if A[0]!=1:
        return 0
    else:
        for i in range(len(A)-1):
            if A[i]+1!=A[i+1]:
                return 0
            else :
                continue
        return 1

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